Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let f(0) = f ' (0) = 0 and f " (x) = sec 4 x + 4, then f(x) =
A
log sec x + 
tan 2 x + 2x 2
B
log cos x + 
tan 2 x + 2x 2
C
log sec x + 
tan 2 x
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
A
Integrate we have
f ' (x) = 
+ 4x + C 1
f ' (x) = tan x + 
+ 4x + c 1
put x = 0
again integrate
f(x) = log sec x + 
+ 2x 2 + c 2
= log secx + 
– 
log sec x + c 2 + 2n 2 put x = 0
c 2 = 0 ∴ 
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